求y=arctan[49x+1/(70x-30)]的导数计算步骤
反函数的求导公式为:[f^(-1)(x)]'=1/f'(y)。对于本题,函数y=arctan[49x+1/(70x-30)]的反函数为:tany=49x+1/(70x-30),此时有:y'=1/(tan'y)=1/(secy)^2=1/[1+(tany)^2],由tany=49x+1/(70x-30)两边平方有:(tany)^2=[49x+1/(70x-30)]^2,即:(tany)^2=[49x(...
求y=arctan[83x+1/(72x-90)]的导数计算
反函数的求导公式为:[f^(-1)(x)]'=1/f'(y)。对于本题,函数y=arctan[83x+1/(72x-90)]的反函数为:tany=83x+1/(72x-90),此时有:y'=1/(tan'y)=1/(secy)^2=1/[1+(tany)^2],由tany=83x+1/(72x-90)两边平方有:(tany)^2=[83x+1/(72x-90)]^2,即:(tany)^2=[...
函数y=arctan(3x+1)+2x的一阶和二阶三阶导数计算
因为:y=arctan(3x+1)+2x,由反正切和一次函数导数公式有:所以:dy/dx=3/[1+(3x+1)^2]+2。二阶导数计算:因为:dy/dx=3x/[1+(3x+1)^2]+2,由函数商的求导法则有:所以:d^2y/dx^2=-3*2(3x+1)*3/[1+(3x+1)^2]^2+0,=-18(3x+1)/[1+(3x+1)^2]^2。三阶导数计算:...
不定积分的求法-不定积分常用方法小结
4.3I=∫x+1+lnx(x+1)2+(xlnx)2dx4.3I=\int_{}^{}\frac{x+1+lnx}{(x+1)^{2}+(xlnx)^{2}}dx(xlnxx+1)′=x+1+lnx(x+1)2(\frac{xlnx}{x+1})^{}=\frac{x+1+lnx}{(x+1)^{2}}??I=∫11+(xlnx1+x)2d(xlnxx+1)=arctan(xlnxx+1)+c\RightarrowI=\int_{}^...